satisfying equations?

0 ⤊

satisfying equations?

a diagram shows a rectangle with length x+4 and width x-1.
the area of the rectangle is 'A' square cms.
therefore A=x^2+3x-4

When A=10, x satisfies the equation x^2+3x-14=0.
Find the length of the rectangle.

2007-01-28 03:46:21 · 2 answers · asked by jenny 1 in Science & Mathematics ➔ Mathematics

2 answers

x^2+3x-4=10
x^2+3x-14=0
x=-3+/-sq.rt.(9+56)/2
=-3/2+/-sq.rt65/2
-3/2+sq.rt65/2
length=5/2+sq.rt.65/2
=6.53cm

2007-01-28 04:25:10 · answer #1 · answered by raj 7 · 0⤊ 0⤋

work it out P.E.M.D.A.S.

2007-01-28 11:50:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋