enthalpy of fusion?

Question

the enthalpy of fusion of ice is 6.02 kJ/mol. the heat of capacity of liquid water is 75.4 J/mol C. what is the smallest number of ice cubes at 0.0 C, each containing one mole of water, necessary to cool 750g of liquid water initially at 30C to 0.0C?

Answer 1

750g of water (molecular weight 18)
corresponds to 750/18 =41.67 moles of water
to cool 41.67 moles of water from 30 to 0 , you need
Q = - 41.67 * 30*75.4 =- 94257 J or- 94.257 Kj

to melt one mole of ice you need 6.02
so you must melt at least 15.66moles of ice and so at least 16 of yuor cubes