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ln (sec e^x) + c ???

2007-01-28 03:02:49 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

e^x sin (e^x) + c

-e^x cos (e^x) + c

- cos e^x + c

sin e^x + c

- tan e^x + c

tan e^x + c

ln (sec e^x) + c

none of these

2007-01-28 04:02:02 · update #1

4 answers

It's Tan(e^x) + C

Read your question carefully, you left out the exponential sign in Sec^2 (ex). It's supposed to be Sec^2(e^2). Otherwise, integrating the expression the way you had it, it's fantastically complicated.

2007-01-28 04:16:42 · answer #1 · answered by Scythian1950 7 · 1 0

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2016-09-28 02:33:11 · answer #2 · answered by ? 4 · 0 0

e^x integrated is just e^x.
sec^2 (ex) is "e tan (ex)" I think.
But you have to solve it by parts because it's a product (e^x is multiplied by sec^2 (ex).

If you don't know how to solve by parts, I don't think I can help you via this! It's too difficult to explain over this!

2007-01-28 03:31:26 · answer #3 · answered by yeraciba 2 · 0 0

Try using integration by parts.

2007-01-28 03:28:57 · answer #4 · answered by Runa 7 · 0 0

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