Terminal Velocity.
2007-01-28 03:05:06
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answer #1
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answered by Black Rabbit 1
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They can fall no faster than their terminal velocity (which depends on the fluid they are falling in and their particular geometry). If you are dropping and object in a vacuum, however, it depends on how long the object is allowed to fall:
v = v0 + g*t
where t is time, v0 is initial velocity and g is the acceleration due to gravity (g = 9.8 m/s^2).
This is, of course, not ALWAYS true since Einstein's theory of relativity says that nothing can travel faster than the speed of light. Once your object reaches a speed close to the speed of light, the speed will depend on the observer's frame of reference.
2007-01-28 12:04:03
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answer #2
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answered by clydesdale1981 3
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The speed at which an object fall depends upon the height, and weight of the object.
2007-01-28 11:11:31
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answer #3
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answered by andrew91025 3
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It's not how fast objects fall because they gain speed every second.As they falls, they all fall at a constant acceleration which is -9.8m/s^2.
2007-01-28 11:08:48
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answer #4
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answered by 7
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if we neglect the air resistance then
a body falling from top has a spped of 9.8m/s downwards. after 2 seconds it becomes 19.6m/s and so on.
2007-01-28 11:42:09
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answer #5
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answered by prat_apr89 1
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A free falling objet falls at 9.8 m/s^2
2007-01-28 11:08:46
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answer #6
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answered by manuel w 2
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it will fall with acceleration 9.81ms-2 and then due to resistive forces such as air resistance, there willl be a terminal velocity....
http://en.wikipedia.org/wiki/Terminal_velocity
2007-01-28 12:06:15
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answer #7
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answered by Krish 5
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i think that it's 9.8m/s^2.
2007-01-28 11:09:48
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answer #8
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answered by ♥2cute4u♥ 3
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