g(x) = 1 + 1/x , h(x) = 1 - 1/x , p(x) = 1/x - 1 , q(x) = -2/x . Then if f(x) = [q(x)]/[p(x)], what is f '(x)

2 ⤊

2007-01-28 02:57:15 · 2 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics

2(x - 1)^-2

-2(x - 1)^-2

2(x + 1)^-2

-2(x + 1)^-2

none of these

2007-01-28 04:04:09 · update #1

well, f(x)=2x/(x-x^2). Differentiate that for the result.

2007-01-28 03:05:22 · answer #1 · answered by wigglyworm91 3 · 0⤊ 1⤋

its -2/[(x-1)^2]

2007-01-28 11:38:03 · answer #2 · answered by prat_apr89 1 · 2⤊ 0⤋