a. -94
b. 32
c. -184
d. -142
2007-01-28 02:03:26 · 4 answers · asked by lana l 1 in Science & Mathematics ➔ Mathematics
If p(x) = 4x^3 - 5x^2 + 7x - 10,
and you want to solve for p(-3), just replace every occurrence of x with (-3).
p(-3) = 4(-3)^3 - 5(-3)^2 + 7(-3) - 10
And at this point, keep order of operations in mind.
p(-3) = 4(-27) - 5(9) - 21 - 10
p(-3) = -108 - 45 - 21 - 10
p(-3) = -153 - 21 - 10
p(-3) = -174 - 10
p(-3) = -184
2007-01-28 02:09:05 · answer #1 · answered by Puggy 7 · 1⤊ 0⤋
p(-3) = 4(-3)^3 - 5 (-3)^2 + 7(-3) - 10 = -184
so the answer is c
2007-01-28 02:09:51 · answer #2 · answered by Anonymous · 1⤊ 0⤋
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2016-12-16 15:28:16 · answer #3 · answered by hayakawa 4 · 0⤊ 0⤋
the answer is c. -184
p(-3) = 4 (-3)^3 - 5(-3)^2+7(-3)-10
2007-01-28 02:11:50 · answer #4 · answered by imjustmewhatelseshouldibe 1 · 1⤊ 0⤋