oC ?
The specific heat capacity of solid water is 2.03 J g-1 oC -1
Use a negative sign in your answer if heat is removed.
2007-01-28 01:09:36 · 5 answers · asked by Beth F 1 in Science & Mathematics ➔ Chemistry
First the number of moles of water must be converted to mass. As the molecular mass of water is 18, then 4.32 moles would have a mass of 77.76g. Liquid water has a specific heat capacity of 4.2kJ/kg/K.
The process should be split into three parts. The first part is the cooling of water from 43 degree Celsius to 0 degree Celsius. The heat removed can be calculated from the mass of water multiplied by its specific heat capacity muliplied by the temperature change. hence for the first part 77.76*4.2*43/1000 (to convert grams into kg)=14.04kJ.
Next water freezes (with no temperature change) and the latent heat of fusion has to be added to part one. The latent heat of fusion of ice at 0 degree Celsius is 334 kJ per kg. Ths results in 334*77.76/1000 energy been given up, or in other words 25.97kJ has been removed.
The final part is the subcooling of the ice from 0 degree to -18 degrees. The heat removed can be calculated from the mass of Ice multiplied by its specific heat capacity (for ice this is assumed to be 2.1kJ/kg/K) multiplied by the temperature change. Hence for the third part 77.76*2.1*18/1000 (to convert grams into kg)=2.94kJ.
The heat that is removed from the process is the sum of all three parts i.e 14.04+25.97+2.94=42.95kJ is removed from the process.
This is the answer.
2007-01-28 02:17:33 · answer #1 · answered by The exclamation mark 6 · 1⤊ 0⤋
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2016-05-16 16:51:52 · answer #2 · answered by Cynthia 4 · 0⤊ 0⤋
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2016-12-17 04:25:06 · answer #3 · answered by ? 3 · 0⤊ 0⤋
4.32moles means thr iz exactly 77.76 grams of water.
According to the formula (MCdelta theta)
heat required iz 77.76*2.03*(43-(-18))= 9629.0208J = 9.63KJ
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2007-01-28 01:18:29 · answer #4 · answered by Mr Myth 3 · 0⤊ 1⤋
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2007-01-28 01:16:47 · answer #5 · answered by Anonymous · 1⤊ 1⤋