120 times p = lines in a book
(120 + 20 ) times p-3 = same number of lines
so 120p = 140p - 420
subtract 420 each side
120p + 420 = 140p
subtract 120p each side
420 = 20p
p = 21
original number of lines per page is 21
21 x 120 = 2520
18 x 140 = 2520
tada!!!!!!!!!!!!!!!!!
2007-01-28 00:03:58
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answer #1
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answered by tomkat1528 5
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Hi MS,
If at the start we have 120 pages, and 'p' lines in each page, we have a total of
120*p lines
Now, if the number of lines are reduced by three on each page the number of pages would need to be increase by 20 to give the
same amount of writing space. So, the new number of pages is 140 (120 + 20).
Since the writing space is same, so
120*p = 140 * (p-3)
120*p = 140*p - 420
420 = 140*p - 120*p = 20*p
So,
420=20*p
p=21
So, there were 21 lines on the page originally.
2007-01-28 08:17:54
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answer #2
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answered by Saumya Gupta 1
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120 p = x = 140 (p- 3), solve for p, 20 p - 420 = 0, p = 21.
Explanation let x equal the total number of lines, Known 120 * p = X
120 + 20 = 140 pages in new layout. 140* l = X and l = p-3. follow the algbra above
2007-01-28 08:47:23
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answer #3
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answered by mathman241 6
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how you doin' MS?
if at the start we have 120 pages, and 'p' lines in each page, we have a total of 120*p lines. right?
now, they tell us that if each page had (p-3) lines, we had to add 20 pages (120+20 = total 140 pages) to get the same number of lines alltogether. we have an equation:
120*p = 140 * (p-3)
we open the parenthesis (???)
120*p = 140*p - 420
we move 120*p to the right side with a minus sign, and move 420 to the left side with a positive sign. we get
420 = 140*p - 120*p = 20*p
we divided both sides of the equation by 20, getting
420 / 20 = 21 = p
that means that originally, each page had 21 lines. got it?
2007-01-28 08:05:52
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answer #4
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answered by roy_gavish 2
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p*120=140*(p-3)=140*p-420
20*p=420
p = 420/20 = 21 lines on the original page.
2007-01-28 08:10:56
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answer #5
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answered by Jano 5
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120p=140(p-3)
20p=420
p=21
2007-01-28 08:07:29
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answer #6
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answered by Jesus Christ 1
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