In the physical sciences, Pascal's law or Pascal's principle states that the fluid pressure at all points in a connected body of an incompressible fluid at rest, which are at the same absolute height, are the same, even if additional pressure is applied on the fluid at some place. k On the other hand, the difference of pressure between two different heights h1 and h2 is given by:
where Ï (rho) is the density of the fluid, g the acceleration due to gravity, and h1, h2 are elevations. The intuitive explanation of this formula is that the change in pressure between two elevations is due to the weight of the fluid between the elevations.
Note that the variation with height does not depend on any additional pressures. Therefore Pascal's law can be interpreted as saying that any change in pressure applied at any given point of the fluid is transmitted undiminished throughout the fluid.
2007-01-28 06:24:31
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answer #2
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answered by ifureadthisur2close 2
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(dp/dz) = -(rho*g)
this is a basic pressure-height relation of fluid static, with p=pressure, z=height, rho=density of the fluid and g=gravitational constant.
for a lower level of studies, we only need to consider an incompressibe fluid (in reality, fluid are compressible!!). so, for an incompressible fluid, rho (density of the fluid) are constant. so, (dp/dz) = -(rho*g) = constant.
by intergration, we'll get
P1 - P2 = rho*g*(z2 - z1). <-- pascal's law.
where P1=pressure at point 1, P2=pressure at point 2, rho=fluid density, g=gravitational constant, z2=height at point 2 from free surface and z1=height at point 1 from free surface.
*above is the derivation of pascal law.
pascal law stated that the pressure in an incompressible fluid are same regardless the size and shape of the container. only the heigth affect the pressure magnitude in the fluid. i hope you see what is mean by p-p0 = rho*g*(z-z0).
rho and g are constant. see? only the z=height affect the pressure diffrence.
2007-01-28 08:15:48
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answer #3
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answered by Anonymous
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