physics help 10?

Question

A 0.330-kg volleyball is thrown vertically downward with a speed of 0.150 m/s. It takes it 0.0655 s to reach the ground. What is the magnitude of its momentum just before it hits the ground?
a. 0.212 kg x m/s
b. 0.262 kg x m/s
c. 0.163 kg m/s
d. 0.0216 kg x m/s

Answer 1

apply

s=ut+1/2at^2 in which ut=0
from this ais known and t is known and hence we can find s

now apply
v^2-u^2=2as
and find v
and apply
mv =momentum