Here are the rules:
sin(pi/15) = sin(2pi/5 - pi/3) = sin(pi/6 - pi/10)
sin(a-b) = sin(a)cos(b)-sin(b)cos(a)
sin(pi/10)=cos(2pi/5) = (√5 - 1)/4
cos(pi/6)=sin(pi/3) = √3/2
cos(pi/10)=sin(2pi/5) = √[(5 + √5)/8]
sin(pi/6)=cos(pi/3) = 1/2
Good luck. I am not able to do it.
Historically, this is a key part to the solution of Van Roomen's problem.
2007-01-27
17:08:54
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3 answers
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asked by
larry_freeman2
1
in
Science & Mathematics
➔ Mathematics
This is the solution according to Mathworld.wolfram.com:
Checkout:
http://mathworld.wolfram.com/TrigonometryAnglesPi15.htm
I will also accept a proof that the equation is wrong.
2007-01-28
04:36:35 ·
update #1
This is the solution according to Mathworld.wolfram.com:
Checkout:
http://mathworld.wolfram.com/TrigonometryAnglesPi15.html
I will also accept a proof that the equation is wrong.
2007-01-28
04:38:03 ·
update #2
To be clear the parentheses should be around the entire equation so that is:
(1/4)sqrt{7 - sqrt(5) - sqrt[30 - 6*sqrt(5)]}
It should be:
(1/4)√{7 - √5 - √(30 - 6√5)}
So, it is not a negative number. Sorry that this wasn't clear.
Also, the two numbers are equal so there won't be a proof that the equation is wrong.
2007-01-28
04:49:51 ·
update #3