what is the volume of solution of sulfuric acid with a 18.663 M concentration and a Normality of 1.572?

Answer 1

Your question makes no sense.

1.Both molarity and normality are expressions of concentration so without additional info it is impossible to find the exact volume

2. N=aM, where a for acids is the number of H+ per acid molecule. For H2SO4 a=2 so N=2*18.663 = 37.326. You can't have a solution that is 18.663 M and 1.572 N H2SO4 at the same time.

If you mean that it contains 1.572 gr-eqs (equivalents) acid then
N=gr-eq/V =>V=gr-eq/N= 1.572/37.326= 0.0421 L =42.1 mL

Answer 2

Normality = Molarity x Equavalent X

1.572=18.663M x X
X=0.0842


Normality = Equivalent of X/Liter

1.572 = 0.0842/ liter

Liter= 0.0842/1.572

0.054 liter=volume