A constant net force of 410 N is applied upward to a stone that weighs 32 N. The upward force is applied ...?

Question

A constant net force of 410 N is applied upward to a stone that weighs 32 N. The upward force is applied through a distance of 2.0 m, and the stone is then released. To what height, from the point of release, will the stone rise?

Please help me with this problem.
I'm having trouble solving it.

I asked this question once before, but I was confused with the answers received.

Answer 1

Well !... for starters... don not expect us to solve your homework for you...
the solving of the mentioned problem requires understanding the basics of dynamics. it ain't einstein stuff... prolly you dozed off in the class...
Anyways!...
applying newtonian laws of mechanics...
work= force x distance
hence in this case,
410 x2=820 joules is the net force applied on the stone
this should be resolved by work done by the stone= 32 x (unknown distance)
hence, 32 x (unknown distance)= 820
Now, you do the math!!
... the only unresolved variable in this case, is the aspect of gravity that you haven't mentioned... hence i assume it is being conducted in a zero gravity n zero resistance environment

Science can be and is a lot of fun!!...take it up mate!

Answer 2

artwork executed by technique of the stress(410N) on the stone=410*2=820 Joules improve contained in the flexibility of the stone= improve in P.E + Kinetic power ok received. = 32*2 +ok = sixty 4+ok Joules. Equating both: sixty 4+ok = 820 which substances ok = 756 Joules. assume the stone rises up a distance h meters from the area of launch to the utmost aspect the position it includes relax. Then the Kinetic power of the stone adjustments into its ability power. So: 32h =756 which substances h=756/32 =23.625 m answer