Could anyone tell me how to solve 27x^3 =1 ? thanks alot?

Question

Could anyone tell me how to solve 27x^3 =1 ? thanks alot

Answer 1

27x^3 = 1
Subtract 1 from both sides :
27x^3 - 1 = 0
Change to difference of two cubes form :
(3x)^3 - 1^3 = 0
Factorise : e.g. a^3 - b^3 = (a - b)(a^2 + ab + b^2)
(3x - 1)(9x^2 + 3x + 1) = 0
Therefore, 3x - 1 = 0, implying that x = 1/3
or, 9x^2 + 3x + 1 = 0 implying that x = -1/6 ± i*sqrt(3)/6,
after using the quadratic formula.
The 3 solutions are thus: 1/3, -1/6 + i*sqrt(3)/6, -1/6 - i*sqrt(3)/6.

Answer 2

x= 1/3

Answer 3

Solve: 27x^3 =1

First: isolate "x^3" on one side > divide both terms by "27"...

(27x^3)/27 = 1/27

Sec: cancel "like" terms...

x^3 = 1/27

Third: find the cube root of "3" on both sides...

V`(x^3) = V`(1/27)

x = 1/(V`27)

x = 1/(V`3*3*3)

x = 1/3

Answer 4

First get x^3 on one side. This can be done by dividing both sides by 27, leaving you with x^3 = 1/27.

To get rid of the power-to-3, just take the cube root of both sides:

(x^3)^(1/3) = (1/27)^(1/3)
x = (1/27)^(1/3)

Distribute the cube root through both the numerator and denominator:

x = (1^(1/3)) / (27^(1/3))
x = 1 / 3

Answer 5

Sure.
27x^3 = 1
x^3 = 1/27
cube root (x^3) = x = cube root(1/27) = 1/3
x = 1/3

Simple, no?


Doug

Answer 6

27x^3=1
x^3= 1/27 (divided 27 for both sides)
x= 1/3 (take a cube root)

Answer 7

The order of operations indicates that exponentiation comes before multiplication.

Divide both sides by 27. This will yield:

x^3 = 1/27

To solve for x, take the cube root of both sides.

Answer 8

First divide both sides by 27: x^3 = 1/27

Then do the cube root of both sides, since the cube root of x cubed is just x. You can figure the cube root of 1/27.

Answer 9

cubed root of 1 divided by 27

Answer 10

.a million(x+50)+.1x=6 circumstances .a million by potential of whats interior the brackets keep in ideas BEDMAS .1x+5+.1x=6 flow the 5 to the different edge in order to isolate the variable x (once you flow a kind to the different edge of the equals signal it is going to change into adverse) .1x+.1x=a million convey mutually like words .2x=a million divide .2 on both edge to isolate x .2x/.2x=a million/.2 x=5 you are able to plug 5 again into the equation and if each edge are equivalent then its top in case you pick to envision your answer.