determine the accumulation point of the set z=(-1)^n(1+i)(n-1/n) for n=1,2,...,n?

Answer 1

I'm guessing that the 'i' is the unit imaginary. But, in any case, the function doesn't have an accumulation point since it diverges ('almost' linearly with n)) to ±(∞+i∞) as
n -> ∞ (It's ± since -1^n alternates sign with even and odd values of n)

OTOH it *does* converge to the unit pole on a Riemann sphere, if you want to do the topological mapping ☺


Doug