a. 1 real, irrational
b. 2 real, rational
c. no real
d. 1 real, rational
2007-01-27 11:03:47 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
b.
2007-01-30 11:37:17 · answer #1 · answered by lana l 1 · 0⤊ 0⤋
I respectfully disagree with the posted answers.
Your equation is
x²-12x+36=0.
The discriminant is 144-4(36)=0,
so the equation has a double root at x=6.
If you count a double root as 2 roots the answer is b),
but if you count it as just one root, the answer could
also be d).
Really, d) should read: 2 real, rational, equal
and b) should read 2 real, rational, distinct.
2007-01-27 11:31:51 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
If the value of the discriminate is positive, there are 2 solutions and since a dozen people already solved the problem, I'm not going to go over that but the 2 soultions are positive radical 128 ad negative radical 128. Or +/- radical 128.. you should reduce accordingly.
on future problems... If the discriminate is negative, there are no solutions and if the discriminate is 0, there is only 1 solution.
b^2 - 4ac > 0, 2 real solutions
b^2 - 4ac < 0, no real solutions
b^2 - 4ac = 0, one real solution
2007-01-27 11:25:06 · answer #3 · answered by candijwheat 1 · 0⤊ 0⤋
x^2 + 20 = 12x - 16
Move everything to the left hand side,
x^2 - 12x + 20 - 16 = 0
x^2 - 12x + 4 = 0
Solving for the discriminant,
b^2 - 4ac = (-12)^2 - 4(1)(4) = 144 - 16 = 128
128 is not a perfect square; therefore, your answer is
Two real, irrational.
2007-01-27 11:09:41 · answer #4 · answered by Puggy 7 · 0⤊ 0⤋
x^2+20=12x-16?
x^2 -12x +36 = 0
discriminant = sqrt(12^2 +64)
This is positive so there are two real, rational roots.
2007-01-27 11:13:37 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
a. 1 real, rational
x=6
2007-01-27 11:23:27 · answer #6 · answered by quasar 1 · 0⤊ 0⤋
2^ 7x+9 2x^2=-7 2x-#=-9 = 2 in the past negetive selection x 2 equale 0 yet all selection 2 x 2 ^ might equivalent in accordance with negetive seven ^ negetive selection plus change 2 for uneven selection equals negetive 9. 7 x plus 9 7 circumstances undemanding equation of ruled out selection cant mutiply a negetive first rule +9 equals equation -9 plus 9 equals 0
2016-11-01 10:58:03 · answer #7 · answered by ? 4 · 0⤊ 0⤋
x^2 + 20 = 12x - 16
x^2 - 12x + 36 = 0 (a = 1, b = -12, c = 36)
Δ = b^2 - 4.a.c = 12^2 - 4.1.36 = 0
So, being Δ = 0, there are two real (racional) and equal roots...
x = -(b +/- sqrt(Δ))/(2.a)
x = (12 +/- 0)/(2.1)
x = 6
2007-01-27 11:09:53 · answer #8 · answered by Anonymous · 0⤊ 0⤋
b. 2 real rational
2007-01-27 11:08:28 · answer #9 · answered by black_lotus007@sbcglobal.net 3 · 0⤊ 0⤋
b. 2 real, rational
2007-01-27 11:10:02 · answer #10 · answered by Northstar 7 · 0⤊ 0⤋
b
2007-01-27 11:05:58 · answer #11 · answered by ~Zaiyonna's Mommy~ 3 · 0⤊ 1⤋