a. (2x-7)^2=25
b. (2x-7)^2=5
c. (2x-7)^2= +5
d. 4x^2-28x+24=0
2007-01-27 10:54:13 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Difference of squares first
(2x-7)^2=25
then take the square root of both sides....
2x-7=+/- 5
x=6, 1
so therefore A....
2007-01-27 10:57:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
element the trinomial first: (2x-7)(2x-7) this might then be written as (2x-7)^2=25 you ought to then take the sq. root of the two components to get: 2x-7=5 and remedy a customary 2-step equation (upload 7 and divide with the help of 2 to the two components). you may get the respond of x=6. continuously plug the quantity back into the equation to double verify which you obtain the suited answer. Edit: i did not worry with the +/- facet of the sq. root of 25. yet another answer above mine is extra precise taking that under consideration.
2016-12-17 04:08:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
4x^2-28x+49=25
using the Propert:
(x^2 - 2xy + y^2) = z^2
(x - y)^2 = z^2
4x^2-28x+49 = 25
((2x)^2 - 2.2x.7 + 7^2) = 5^2
(2x - 7)^2 = 5^2 = 25
item a
2007-01-27 11:01:30 · answer #3 · answered by Anonymous · 1⤊ 0⤋
a.
This is called completing the square.
But the equation you were given has the square already completed on the left side of the equation. All you have to do is factor it as its square root (2x-7) times itself.
2007-01-27 10:59:39 · answer #4 · answered by actuator 5 · 0⤊ 0⤋
a because the other 3 aren't the same equation as the first one
2007-01-27 11:04:24 · answer #5 · answered by Anonymous · 0⤊ 0⤋