2007-01-27 10:43:51 · 7 answers · asked by tray j 1 in Education & Reference ➔ Homework Help
ok. from da top.
2x+3y=90
3y=90-2x
y=30-(2\3)x
there ya go buddy
2007-01-27 10:49:13 · answer #1 · answered by Dmaista 2 · 0⤊ 0⤋
You need to get it into slope intercept (y=mx+b).
2x + 3y = 90
3y = -2x + 90 Subtract 2x from both sides.
y = (-2/3)x + 30 Divide both sides by three to isolate the y.
2007-01-27 10:55:52 · answer #2 · answered by kneu93 3 · 0⤊ 0⤋
Slope-intercept form is y=mx + b. So isolate y on one side of the equation and solve. y= -2x/3 +30.
2007-01-27 10:48:43 · answer #3 · answered by kiwebl246 1 · 0⤊ 0⤋
write each equation in slope-intercept form 2x+3y=90?
2x + 3y=90
-2x -2x=
3y= 90-2x
/3 /3
y=3/90-2x
then you switch it up a little and do x.
2x+3y=90
-3y -3y
2x=90-3y
/2 /2
x=2/90-3y
2007-01-27 10:55:43 · answer #4 · answered by iTzUhHaPpyHeLL 3 · 0⤊ 0⤋
Slope intercept form: y=mx +b
The point is to get "y" by itself.
Subtract 2x from each side, then divide each side by three.
2007-01-27 10:49:11 · answer #5 · answered by Krimo 2 · 0⤊ 0⤋
y=mx + c
2x+3y=90
y = -(2/3)x + 30 x = -(3/2)y + 45
y - slope x - slope
2007-01-27 10:55:23 · answer #6 · answered by harsha s 2 · 0⤊ 0⤋
y= -2/3x+30
2007-01-27 10:54:58 · answer #7 · answered by CSfan20 2 · 0⤊ 0⤋