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Could anyone please help me out, with the full working out and solution to each problem. thanks

QUESTION 2) Use the remainder theorem to find the remainder when 2x^4 - x^2 + 3x - 2 is divided by (2x-1)

QUESTION 3) When x^4 + ax^2 + bx - 2 is divided by (x-1) the remainder is -2, and when it is divided by (x+1) the remainder is -6. Find the values of a and b.

QUESTION 5) The polynomial x^3 +px^2+6 is exactly divisible by (x+2) and (x-3). Find the values or p and q.

QUESTION 7) If x^3 + 4x^2 - 3x +2 = (x+1)(ax^2+bx+c) + d for all the values of x, find the values of a,b,c, and d.

QUESTION 8) If x^3 + 4x^2 - 12x + 14 = x^3 + (mx + n)^2 + 5 for all the values of x, find the values of m and n.

QUESTION 9) If x^2 = a(x+2)^2 + b(x+2) + c for all values of x, find the values of a,b,c.

THANKS HEAPS IN ADVANCE..

2007-01-27 10:19:40 · 2 answers · asked by NFLS121a 1 in Education & Reference Homework Help

hey.. ops QUESTION 5 is wrong.. sorry its missing the q...

5) x^3 + px^2 + qx + 6 loll...

2007-01-27 11:45:44 · update #1

2 answers

2) The remainder theorem does not apply here; it only works when the divisor is in the form "x-r" where r is a constant. In this case you just have to use long division:
(2x^4 - x^2 + 3x -2)/(2x-1) = x^3 - 1/2x^2 - 1/4x - 9/8 remainder = 7/8

3) The remainder theorem applies here because the two divisors are both in the form "x - r". To find the remainder you substitute "r" in for "x". This results in the remainder. Make that equal to the remainder that is given and solve the system of equations...
Ans: Substituting the first r (= 1) into the dividend, we get "a + b = -1". Now, substituting the second r (= -1) into the dividend, we get "a - b = -5". Solving the resulting system of equations, we get (a,b) = (-7/2, 3/2).

5) You seem to be missing a "q" in the original equation, as it appears in your answer. I am assuming that instead of "6" you meant "6q", which is the logical place for the variable. If a polynomial f(x) is exactly divisible by "x - r", then f(r) = 0. Using this principle, we see that "2p+3q=4". Also, "3p+2q=-9". Solving the resulting system of equations we get (p,q)=(6,-7).

Now, unfortunately I have to go eat supper. If you want more help please feel free to contact me at wigglyworm91@yahoo.com, or IM me at wigglyworm91 if I am available.

I'll check if you wrote back after supper.

2007-01-27 11:01:46 · answer #1 · answered by MDMMD 3 · 0 0

DUDE!!!! MAYBE IF YOU'D PAY ATTENTION IN MATH CLASS YOU WOULD BE SMART!!!!

2007-01-27 19:15:29 · answer #2 · answered by VdogNcrck 4 · 0 1

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