it's just a rectangle with two lines crossing each other from corner to the other. kinda like an x. then there is an 8 on one line and a 10 on the other.
2007-01-27 10:13:39 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
If the diagonals are not the same length, it is not a rectangle.
2007-01-27 10:21:11 · answer #1 · answered by catarthur 6 · 0⤊ 0⤋
The diagonals of a rectangle ar equal so one cannot be 8 and the other one 10. Perhaps you have been given the length of the diagonal = 10 and the length = 8, but not given the width.
Then you could get width by Pythagorean theorem to be = 6.
Then area would be 6*8=48 units^2
The diagonals of a rectangle also bisect each other. It matters a lot where the 8 and 10 were placed.
2007-01-27 18:33:31 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
Without seeing the problem, I think what you have is the length of the diagonal (10) and the length of one side (8). Use c^2 = a^2 + b^2 for the right triangle and find that the other side is 6. Then the area is 8x6 = 48
2007-01-27 18:23:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋
As an afterthought:
After I wrote the following, I saw namenot's response, and I think he is correct (that you've been given a diagonal and a side). But if you had been given diagonals, the following would apply:
If it's a rectangle, the diagonals are equal, and they intersect at their midpoints.
If it's a parallelogram, the diagonals intersect at their midpoints, but are not necessarily equal.
If it's a rhombus (four equal sides), the diagonals intersect at their midpoint at right angles, and are not necessarily equal.
If all you know is the lengths of the diagonals, you can not determine which type of shape you have, or what its area is. If you know the lengths of the diagonals and where they intersect, and at what angle they intersect, then you can determine the shape and its area. and if you know the lengths of the diagonals and the type of shape you have (rectangle, rhombus, etc.), you MAY be able to solve for its area, but not if it's a parallelogram. (If it's a parallelogram, you also need to know the angle between the two diagonals.
2007-01-27 18:29:01 · answer #4 · answered by actuator 5 · 0⤊ 0⤋
This is not a rectangle!!!....If the line from one corner to the other is 8 and the other line is 10....then theory prove that this figure is not a rectangle but a parallelogram.
Theres must be some other information about this figure...like angles or side values....
2007-01-27 18:20:46 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Sounds like you're being given diagonals. Diagonals would dissect the rectangle into right triangles, and you'd use the pythagorean theorem and the known element(s) to find the missing element(s) and then find the area.
If you know trig you could use this as well to find the missing elements but it sounds like you're not into trig yet.
2007-01-27 18:22:47 · answer #6 · answered by Joni DaNerd 6 · 0⤊ 0⤋
Well, I guess you could find the area one of the right triangles that forms from the X and then multiply it by two. A=1/2bh Even though that is basically the same as length times width, just pointless extra work.
2007-01-27 18:21:30 · answer #7 · answered by kiwebl246 1 · 0⤊ 0⤋
If the diagonals are not the same length, it's not a rectangle.
2007-01-27 18:21:12 · answer #8 · answered by poorcocoboiboi 6 · 0⤊ 0⤋
If you are given the diagonal and any one other element, you can compute an area. It may require a bit of algebra to do so, depending on what you are given.
2007-01-27 18:19:41 · answer #9 · answered by Anonymous · 0⤊ 0⤋
If you could describe where the 10 was and where the 8 was I believe I could solve this for you.
2007-01-27 18:22:21 · answer #10 · answered by bruinfan 7 · 0⤊ 0⤋