58.37
if you really don't know how to do that,
USE A CALCULATOR!!!
2007-01-27 10:14:29
·
answer #1
·
answered by Anonymous
·
0⤊
1⤋
This is a simple concept.Whenever you divide a number by the power of 10s,you have to shift the decimal point to the left according to number of zeroes.In this problem you've to divide a number by 100,which has two '0's,so shift the decimal point to the left two times in 5837
1.5837/100
2.583.7 --> for first '0'
3.58.37 --> for second '0'.
so the answer is 58.37
If you want to divide the same number by 1000,which has 3 '0's shift the decimal point to the left 3 times.Hope this helps you.
2007-01-27 18:08:25
·
answer #2
·
answered by Eshwar 5
·
0⤊
0⤋
anything divided by 100 is the same with the decimal place moved 2 to the right. Easy way to remember this is:
the number of zeros is the number of places moved.. if you are dividing, move to the right. If you are multiplying move to the left.
5837/100=58.37
5837/1000=5.837
5837*100=583700
etc etc etc
2007-01-27 18:27:42
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
just move the decimal point by the same amount as you have zeroes. Since you have 2 zeroes, move the decimal point 2 places to left. You will have 58.37.
2007-01-27 19:04:04
·
answer #4
·
answered by Victoria 2
·
0⤊
0⤋
58.37, once you learn math you will learn how easy that is. If it is 100 you just move the decimal over 2 places.
2007-01-27 18:11:49
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
move the decimal place 2 places to the left
5837. becomes 58.37
2007-01-27 19:07:18
·
answer #6
·
answered by Dave aka Spider Monkey 7
·
0⤊
0⤋
58.37
move the decmial over 2 spaces
2007-01-27 18:38:04
·
answer #7
·
answered by princess-of-somany 3
·
0⤊
0⤋
58.37
this is simple math, all you have to do is move the decimal point two spaces to the left
hopes this helps
2007-01-27 18:08:52
·
answer #8
·
answered by Anonymous
·
1⤊
0⤋
58 remainder of 37. Math is my fav. subject
2007-01-27 18:13:55
·
answer #9
·
answered by Skyy00 1
·
1⤊
0⤋
58.37
2007-01-27 18:10:37
·
answer #10
·
answered by Nabiha... 4
·
0⤊
0⤋