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2007-01-27 09:28:43 · 12 answers · asked by tray j 1 in Science & Mathematics Mathematics

12 answers

Please state a question > what needs to be done? I assume you have to find out if the point is a solution of the equation.

First: place the values in the equation...

3(0) + 5(9) = 15

0 + 45 = 15

45 = 15

False - the point isn't a solution because the numbers are not the same.

2007-01-27 11:46:43 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0 1

purely %. any fee for x and sparkling up for y. Or %. any fee for y and sparkling up for x. to illustrate x = 0: 3(0) + 5y = 15 5y = 15 y = 3 So one answer pair is (0, 3) Or try y = 0: 3x + 5(0) = 15 3x = 15 x = 5 So yet another answer pair is (5, 0) How approximately x = -5: 3(-5) + 5y = 15 -15 + 5y = 15 5y = 30 y = 6 So (-5, 6) is yet another pair. you would be able to desire to get fractions, yet those are valid too: x = a million 3(a million) + 5y = 15 5y = 12 y = 12/5 yet another answer is (a million, 12/5)

2016-11-01 10:50:35 · answer #2 · answered by Anonymous · 0 0

(0,9) 3x+5y=15
0=0
0=0 9=9
0=0 9=9 3=3
0=0 9=9 3=3 x=x
0=0 9=9 3=3 x=x 5=5
0=0 9=9 3=3 x=x 5=5 y=y
0=0 9=9 3=3 x=x 5=5 y=y 15=15

I'm a genius

2007-01-27 09:37:35 · answer #3 · answered by Anonymous · 1 1

3x+5y=15
3*0+5*9=15
0+45=15
45=15
False

but that is if 0=x and 9=y

2007-01-27 09:35:25 · answer #4 · answered by Anonymous · 1 1

3(0)+5(9)=15
0+45=15
45=15

45 can't be equal to 15, therefore, (0,9) is not the solution.

2007-01-27 09:32:22 · answer #5 · answered by      7 · 1 1

3(0)+5(9)=15
5(9)=15
45≠15

Not true!

The correct ordered pair should have been (0,3):
3(0)+5(3)=15
5(3)=15
15=15

I hope this helps!

2007-01-27 10:24:46 · answer #6 · answered by Anonymous · 0 1

3(0)+5(9)=15
0+45=15
45=15
Not a solution
No sh**

2007-01-27 09:32:32 · answer #7 · answered by Liza 2 · 1 1

check your math book and make an effort

2007-01-27 09:33:21 · answer #8 · answered by sammy 5 · 2 0

No, it is not a solution to the equation.

2007-01-27 09:38:18 · answer #9 · answered by diogenese19348 6 · 2 0

what is the complete objective of this question?

2007-01-27 09:32:47 · answer #10 · answered by yiohon 2 · 3 0

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