A baseball is hit nearly straight up into the air with a speed of 39 m/s.?

Question

A baseball is hit nearly straight up into the air with a speed of 39 m/s.
(a) How high does it go?
m
(b) How long is it in the air?
s

Answer 1

Vo= 39, Vf=0, a=g=-9.8
Vf=Vo+2ah
0=39 + 2*-9.8*h
solve for h.
h=1/2*a*(t squared)
solve for t then multiply by 2.

Answer 2

The answers given are correct assuming no drag on the baseball. That is, the height given is the maximum possible if the ball were in a vacuum. So, it won't go that high. Anyway, gives you an idea as to why the roof of a covered baseball stadium needs to be so darn high up there!

Answer 3

even if it is in truth hit instantly up, all of us recognize all of its speed is vertical; understanding that gravity slows gadgets on the speed of 9.8m/s/s, then all of us recognize the article will attain its apex in a time of 22m/s / 9.8m/s/s = 2.24 s do not forget that the article has 0 vertical speed at apex hence, the entire time in air is two times this, or 4.48s you'll locate its max top from vf^2=v0^2 + 2ad vf=very last speed =0 at apex v0=initial velocit =22m/s a=grav =-9.8m/s/s d=distance to be discovered so that you've 0^2=22^2-2*9.8*d remedy for d and that is your max ht

Answer 4

ThatGuy gave you the right answers, but I thought you should know the formulas to use. the poo goo had the right formulas in mind but messed up the math.

a) Vf^2 = Vo^2 + 2+(-g)*y

b) y = Vo*t + (1/2)*(-g)*t^2
is one way to do it, but this other way is easier.
Vf = Vo + (-g)*t

In both a&b, Vf will be 0 when it's at the highest point.
And -g = -9.8 m/s^2.

Answer 5

whenever i ask a question, even if it's the simplest one, they can't offer me a proper informed answer on this website. what happened to people who actually make the effort to answer?

Answer 6

(a) y = 77.6 m



(b) t = 3.98 s