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and accelleration during the turn

Correct Answer = 71 and 3.9
need to know how you get it tho

2007-01-27 07:36:23 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

The delta in velocity is a vector calculation and is 50*sqrt(2) km/hr = 71 km/hr
convert 50*sqrt(2) km/hr to m/s = 19.6 m/s
acceleration = 19.6 m/s / 5s = 3.9 m/s/s

2007-01-27 07:45:52 · answer #1 · answered by feanor 7 · 0 0

Velocity is a vector quantity. The numerical aspect of your velocity change remains constant in this example. The acceeleration is in the change of direction, not in a change of speed. The change is 90deg/5s or 18deg/s.

2007-01-27 08:02:02 · answer #2 · answered by John R 2 · 0 0

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