2007-01-27 07:31:29 · 14 answers · asked by CelticMoonGoddess 2 in Science & Mathematics ➔ Mathematics
Yes because if you substitute -10 to x you get 9 + 40 =49
Since 49 = 49, then -10 is a solution.
2007-01-27 07:36:33 · answer #1 · answered by Aldo 5 · 3⤊ 0⤋
Yes
9 - 4x = 49
- 4x = 40 {subtract 9 from both sides}
x = - 10 {divide by - 4}
2007-01-27 07:38:05 · answer #2 · answered by Anonymous · 2⤊ 0⤋
YES BECUZ 9-4(-10)=49 9+40= 49 DO NEGATIVES MAKE A POSITIVE
2007-01-27 07:37:26 · answer #3 · answered by Anonymous · 1⤊ 0⤋
YES!
4 X's -10 = -40
9 - (-40) = 9 + 40 = 49
- X's - = + [a negative number times a negative number always equals a positive integer or number]
2007-01-27 07:39:56 · answer #4 · answered by James R 5 · 1⤊ 0⤋
9-4x=49 subtract 9 from each side
-4x=40 divide both sides by -4
x=-10
not only is -1 A solution, it is the ONLY solution. Good job!
2007-01-27 07:52:36 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋
yes
9 - 4x = 49
9 - 4x - 9 = 49 - 9
- 4x = 40
- 4x/- 4 = 40 / - 4
x = - 10
The answer is x = - 10
Insert the x value into the equation
- - - - - - - - - - - - - - - -
Check
9 - 4(- 10) = 49
9 - (- 40) = 49
9 + 40 = 49
49 = 49
- - - - - - - - - -s-
2007-01-27 07:59:48 · answer #6 · answered by SAMUEL D 7 · 0⤊ 0⤋
4b -7 = 3 - 3b +3b +7 +7 +3b 7b = 10 then divide b = 10/7 ths 4(x-sixteen) = 18 4x - sixty 4 = 18 +sixty 4 +sixty 4 4x = 80 2 divide the two aspects via way of four x = 20.5 good on the grounds it extremely is now 4(x-sixteen) = 8 its going to be distinctive 4x - sixty 4 = 8 +sixty 4 +sixty 4 4x = seventy 2 divide the two aspects via way of four, x = 18
2016-12-16 14:56:36 · answer #7 · answered by Anonymous · 0⤊ 0⤋
u r absolutly correct -10 is the solution to 9 - 4x =49 bc
-4x = 40
x = -10
good job
2007-01-27 07:41:36 · answer #8 · answered by Ryan 1 · 0⤊ 0⤋
yes
9 - 4x=49
-9 -9
-4x=49
-4x/-4 49/-4
x=-10
2007-01-27 07:40:03 · answer #9 · answered by soccergrl4103 3 · 1⤊ 0⤋
No. -14.5 will be the answer
9-4x=49
-4x=49+9
-4x=58
58/-4=-14.5
2007-01-27 07:37:20 · answer #10 · answered by Jeep Driver 5 · 0⤊ 5⤋