Please help me with this algebra problem!?

Question

3a^3 b^4 c^0 / (all to the ^ -4)
2a^4 b^5 c^6

you have to simplify the equation
please explain how to do it don't just give me an answer.
I need to know this for my final!

Answer 1

First, this is not an equation but only an expression

Hopefully, this is what you mean

[3a^3 b^4c^0/2a^4 b^5c^6]^-4

Using x^-1 = 1/x

[2a^4 b^5c^6/3a^3 b^4c^0]^4

Simplify within the [ ] usning x^m/x^n = x^(m - n)

[2abc^6/3]^4

Using (x^m)^n = x^(mn) {2^4 = 16, 3^4 = 81}

16a^4b^4c^24/81

Answer 2

I'm not sure from what you've written which part is all being raised to the -4 power, the top or the bottom.
Anyway, when you raise a power to a power you multiply the exponents. Do that first.
Then simplify some more by doing the divisions...remember that when you divide exponents (and the bases are the same) you subtract the exponents (top - bottom). Also remember that any base (except 0) raised to the 0 power is 1.

Answer 3

3a^3 b^4 c^0 /(2a^4 b^5 c^6 )^-4 =45a^19*b^24*c^24
(3a^3 b^4 c^0 /2a^4 b^5 c^6 )^-4 = (16/81)a^4*b^4*c^24