If ƒ(x) = x + ax, and a = 7/2 if f(3/2)?

Answer 1

I presume that your second "if" should really be read as "what is." Just substitute each number where the symbols appear in f(x):

f(3/2) = 3/2 + (7/2)(3/2) = 3/2(9/2) = 27/4 or 6 3/4 or 6.75.

(You should be able to do each separate operation in your head; a calculator is not needed.)

Live long and prosper.

Answer 2

First: the problem gives you the value for "a" > replace "7/2" with the a-variable in the function...

ƒ(x) = x + (7/2)x

Sec: replace "3/2" with the x-variables in the function...

ƒ(3/2) = 3/2 + (7/2)(3/2)

= 3/2 + (7*3)/(2*2

= 3/2 + 21/4 > use your calculator

= 27/4

Answer 3

Just plug in numbers for a and x:
f(3/2)=3/2+(7/2*3/2)
f(3/2)=3/2+21/4
f(3/2)=6/4+21/4
f(3/2)=27/4 or 6 3/4

I hope this helps!

Answer 4

f(x) = x + ax

a = 7/2 if f(3/2)

Then, by definition of f(x),

f(3/2) = (3/2) + a(3/2)

But a = 7/2, so

f(3/2) = (3/2) + (7/2)(3/2)
f(3/2) = (3/2) + (21/4)
f(3/2) = (6/4) + (21/4) = 27/4

Answer 5

what are u trying to ask? But i think i have an idea.