[(27 - 11)2]/11 + [(24 - 13)^2]/13 + [(25 - 15)^2]/15 + [(22 - 19)^2]/19 + [(28 - 13)^2]/13 =?

Answer 1

[(27-11)^2]/11 + [(24-13)^2]/13 + [(25-15)^2]/15 + [(22-19)^2]/19 + [(28-13)^2]/13

First: solve according to order of operations > PEMDAS >
(), exponents, mulitplication, division, addition & subtraction...

(16)^2/11+(11)^2/13+(10)^2/15+(3)^2/19+(15)^2/13

256/11 + 121/13 + 100/15 + 9/19 + 225/13

Sec: combine the fractions - use your calculator...

= 464839/8151

Or, 57.03

Answer 2

Innermost groupings first...

[(27 - 11)^2]/11 + [(24 - 13)^2]/13 + [(25 - 15)^2]/15 + [(22 - 19)^2]/19 + [(28 - 13)^2]/13 =

[16^2]/11 + [11^2]/13 + [10^2]/15 + [3^2]/19 + [15^2]/13 =

256/11 + 121/13 + 100/15 + 9/19 + 225/13 =

256/11 + 346/13 + 100/15 + 9/19 =

Since I don't want to use numbers too big when operating with fractions, I will transform the improper fractions into integer + ordinary fraction:

(23 + 3/11) + (26 + 8/13) + (6 + 10/15) + 9/19 =

Adding up, and making a slight simplification:

55 + 3/11 + 8/13 + 2/3 + 9/19 =

(note: 8151 = 3 * 11 * 13 * 19)

55 + ( 3 * 741 + 8 * 627 + 2 * 2717 + 9 * 429 ) / 8151 =

55 + (2223 + 5016 + 5434 + 3861) / 8151 =

55 + 16534/8151 =

55 + 2 + 232/8151 =

57 + 232/8151 =

57.02846... (approximately)

Easy calculation, although long and boring. I hope I didn't make any errors. Hope this helps.

Answer 3

[(27 - 11)2]/11 + [(24 - 13)^2]/13 + [(25 - 15)^2]/15 + [(22 - 19)^2]/19 + [(28 - 13)^2]/13 =?

32/11 + 121/13 + 100/15 + 9/19 + 15/13 =
32/11 + 136/13 + 100/15 + 9/19 =
32/11 + 136/13 + 20/3 + 9/19 =
23712/8151 + 85272/8151 + 54340/8151 + 3861/8151 =

167185 / 8151