Given ABC, with A(-3,11) B(5,9), C(1,-3). Show, using relevant calculations, that the segment connecting the m

Question

Given ABC, with A(-3,11) B(5,9), C(1,-3). Show, using relevant calculations, that the segment connecting the midpoints of AB and BC is half the length of AC.

Can someone help me with this question? Would I use the distance formula, midpoint formula?

I've already found the answer. Thanks anyway :)

Answer 1

• as they hint you that AC=OA+OC, where OA=OC=AC/2=OB, then O is the center of a circle through points A, B, C, hence angle B=90°; so check it!
■ vector AB=(5-(-3), 9-11) =(8, -2); vector CB=(5-1, 9-(-3)) =(4, 12);
dot product (AB*CB) =32-24 =8 >0; kid, you made a mess!
There must be C(2,-3)!!!

Answer 2

first you should find mid points and then use the distance formula