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Ok so the problems are

add coeficients
Fe + HC2H3O2 -> Fe(C2H3O2)3 + H2

supply correct products and balance adding coefficients
Al + Pb(No3)2 ->
Mg + H3P04 ->
K + HOH ->
Cl2 + CaI2 ->

write correct formulas to show reactants and products then balance

sodium + water -> sodium hydroxide + hydrogen

aluminum + copper (II) sulfate -> aluminum sulfate + copper

2007-01-27 03:20:28 · 4 answers · asked by Taylor 1 in Science & Mathematics Chemistry

4 answers

1. Fe + 6() -> 2() + 3()
2. Al + 3Pb(NO3)2 -> 3Pb + 2Al(NO3)3
3. 3Mg + 2H3PO4 -> Mg3(PO4)2 + 3H2
4. K + HOH -> hmmm, potassium hydroxide is a strong base, which dissociates in water, so I don't think you'd have a reaction here.
5. Cl2 + 2CaI2 -> 2CaCl + 2I2
6. Na + HOH -> NaOH + H2. Sodium hydroxide is a strong base which dissociates in water, so this reaction would not happen.
7. 2Al + 3CuSO4 -> Al2(SO4)3 + 3Cu

2007-01-27 03:35:05 · answer #1 · answered by Anonymous · 0 0

Fe + HC2H3O2 -> Fe(C2H3O2)3 + H2

Rewrite as Fe + H(C2H3O2) -> Fe(C2H3O2)3 + H2 and you can easily see the relationship between products and reactants.

For the other problems, you need a solubility chart (http://intro.chem.okstate.edu/1515SP01/Database/Solub.html) and you need to know formulas and charges for polyatomic ions, as well as strong bases.

See http://chemistry.about.com/library/weekly/bl040903a.htm for poly charges and formulas.

See http://en.wikipedia.org/wiki/Base_(chemistry) for strong bases (you need this info for K + H2O).

You are ready! Solve away, and you will do well on your next test.

2007-01-27 03:35:40 · answer #2 · answered by teachbio 5 · 0 0

2Na + 2H20 ----> 2NaOH + H2 ( this is a very vigorous reaction )


2Al + 3CuSO4 ---> Al2(SO4)3 + 3Cu

[ Aluminum being higher in the metal reactivity series displaces Copper from Copper sulphate ]

2007-01-27 03:36:39 · answer #3 · answered by ? 5 · 0 0

C25H52 + 38O2 → 25CO2 + 26H2O Sr + Cl2 + 3O2 → Sr(ClO3)2 Numbers 3 and 4 make no sense; elements suddenly appear or disappear. Ni(ClO3)2 → NiCl2 + 3O2 (I assume you mean nickel chloride)

2016-03-29 05:00:51 · answer #4 · answered by Anonymous · 0 0

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