let the total no of days =x
let the total amount of work=w
p*10days=w
so p=w/10
similarly
q=w/12
r=w/15
w/10+w/12+w/15=w/x
w(6+5+4)/60=w/x
15/60=1/x
1/4=1/x
so x=4days
2007-01-26 22:58:59
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answer #1
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answered by karikool 3
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Answer: 4 days
P can do 1/10th job a day
Q can do 1/12th job a day
R can do 1/15th job a day.
1/10+1/12+1/15 (need common demoninator which is 60)
6/60+5/60+4/60= 15/60
Together they can do 15/60 th of the job a day.
So, 60 divided by 15 = # of days needed , which is 4.
2007-01-26 23:01:46
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answer #2
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answered by wdy_67 3
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P can do a work in 10 days
divide this job equaly for ten days.
In one day P can finish 1/10 of the job.
Therefore
1/10+1/12+1/15=1/x
x=?
1/x=15/60
x=4 days
2007-01-26 22:59:13
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answer #3
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answered by iyiogrenci 6
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P will do 1/10 of the work in 1 day
Q will do 1/12
R will do 1/15
add them all up and u will get 1/4
thus they need 4 days!(:
2007-01-26 22:53:55
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answer #4
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answered by pigley 4
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2016-10-16 04:17:59
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answer #5
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answered by ? 4
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Their total work rate is the reciprocal of the sum of their individual work rate reciprocals. So their total work rate is
1/(1/10 + 1/12 + 1/15) = 4 days.
Doug
2007-01-26 22:54:29
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answer #6
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answered by doug_donaghue 7
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Why don't you do your own homework?
This question is not difficult.
2007-01-26 23:15:41
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answer #7
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answered by pharmaeng 2
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