a screw gauge has a negative error of 7 divisions .while measuring the diameter of a wire the reading on the main scale is 2 divisions with the 79th circular scale division coinciding with the baseline.if the main scale has 10 div to a cm and the circular scale 100 divisions claculate the pitch,least count ,corrected diameter and corrected radius
2007-01-26 22:20:41 · 2 answers · asked by sufikanchan92 1 in Science & Mathematics ➔ Physics
let's try this,
pitch = 1cm/10 =0.1cm = 1mm
least count = 1mm/100 = 0.01mm
correct diameter = 2.79mm+0.07mm = 2.86mm
correct radius =2.86mm/2 = 1.43
hv fun !!!
2007-01-26 22:43:35 · answer #1 · answered by Sobanath 2 · 0⤊ 0⤋
Pitch is forward travel of gauge face when u turn the knob by one full rotation = 1/10 cm or 1 mm
Least Count = value of 1 divn on main scale/ no of circular marks on round scale
so LC = 1mm/100 = .01 mm or .001 cm
With a negative error of 7 your accurate measure should hv been (79+7)=86th divn after 2 full rotations.
2 full rotation means 2 mm ( or .2 cm)
86 th divn means .86 mm on screw scale
Dia of Wire = 2.86 mm
Radius of wire = 1.43 mm
Convert ur answers to cm or meter if following MKS.
2007-01-27 06:50:03 · answer #2 · answered by poke_a_man 3 · 0⤊ 0⤋