What is a dimensional formula in physics?

Answer 1

read the textbook mate

Answer 2

All physical quantities are derived from the three fundamental quantities namely Mass, length and time.

These three quantities are represented by the symbols M, L and T.

Any physical quantity can be expressed by this simple formula

M^x * L^y * T^z.

x,y and z can have negative or positive or zero value which distinguishes each quantity.

For example energy is represented by the formula;

M^1 * L^2 * T^ (-2)

Now in SI system of units, for making the electrical and magnetic formulae to be as simple as possible, the units of the following quantities are also included as base units.
They are current, temperature, luminous intensity, and the standard amount of substance (unit -mole)

But these quantities can also be expressed in terms of the above three fundamental quantities.

In general we can take any three physical quantities as fundamental and express the other quantities as derived quantity.

This expression is called dimensional formula.

The x, y and z, the powers, are called dimensions of the base quantity involved in the quantity.

One can write the dimensional formula for the three fundamental quantities also.

For example, the dimensional formula for mass is

M^1 * L^0 * T^0.

The dimension of mass is one, the dimension of length is zero and dimension of time is zero in the quantity mass.

Answer 3

A dimensional formula is basically a tool used in physics to check the validity of a formula or to express a physical quantity , say momentum ( p= m.v) in terms of the 3 fundamental units ie. mass, length , and time. [ M.L.T.] each component is raised to its individual exponential value. therefore momentum can be expressed as: p= [ M1.L1.T(-1)] .

Answer 4

It is to verify that each side of equation satisfies the dimension. Say mass M Time T Length L, when a formula is expressed the dimension of equation has to be satisfied to each other.
where F = m.a Where the dimension expressed will be

m = M
a = Velocity / time = (L/T)*(1/T) = L/(T^2)
so multiplying (M*L)/T^2

This dimension need to be satisfied by the other end of the equation.