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A rhombus is a parallelogram with equal sides. This means the angle opposite to B (angle CDA) must be equal to it, and equal 66 degrees. Since a parallelogram's angles total 360 degrees, the total of angles DCB and DAB are 360 - (66*2) degrees = 228 degrees. Since both these angles are equal to each other, they each equal 228 / 2 = 114 degrees. Angle DCA bisects angle DCB, so it splits 114 degrees in two, giving you 57 degrees.

2007-01-26 20:36:34 · answer #1 · answered by jazzy girl 3 · 2 0

Angles B and C are supplementary. They add to 180°. So

C = 180 - B = 180 - 66 = 114

Since ABCD is a rhombus, the diagonals bisect the angles of the vertices. So

Angle DCA = (1/2) Angle C = (1/2)(114) = 57°

2007-01-26 20:38:33 · answer #2 · answered by Northstar 7 · 1 0

If

2016-12-03 02:42:43 · answer #3 · answered by cheathem 4 · 0 0

DCA = ½(360-2*66)/2
DCA = 57°

2007-01-26 21:05:52 · answer #4 · answered by Helmut 7 · 1 0

correct c and d choices.
join A and C
ABC is isosceles triangular
base angle is 57
ACD is the same angle.
hence the answer is 57

2007-01-26 20:48:38 · answer #5 · answered by iyiogrenci 6 · 1 0

if i am not wrong
DCA=57

2007-01-26 20:37:33 · answer #6 · answered by 99%cocoa 1 · 0 1

57 degrees...sure about it

2007-01-27 01:05:55 · answer #7 · answered by Shruti G 1 · 0 0

A) 294
B) 66
C) 294
D) 66

2007-01-26 20:36:18 · answer #8 · answered by dewaddictman 2 · 0 4

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