How many kJ of heat energy are released when 2.1 kg of propane are burned?

Question

By the way, the reaction for the combustion of propane is C3H8(l) + 5O2(g) → 3CO2(g) + 4H2O(g).

And, for that equation ΔH = -2220 kJ/mol.

I greatly appreciate any help!

Answer 1

This is done, using the enthalpy change for the burning of 1 mol of propane with 5 mol of Oxygen and that the limiting reagent is propane

1)Convert the amt of propane to grams: 2100g
2)Calculate the no. of mol of propane: 2100/ (12x3+8x1)= 47.727 mol
3) Total enthalpy change: 47.727 x -2220 kJ= -105954.545 kJ

Jus to take note, this is an exothermic reaction, therefore the enthalpy change value is negative

Answer 2

tHE AMOUNT BUSH/PACHAURI PONZIS FART IN CO2