2007-01-26 17:41:50 · 6 answers · asked by Nadare 2 in Science & Mathematics ➔ Mathematics
For both of your questions, divide the polygon into triangles with the sides of the polygon as one side of each triangle and lines to the center of the polygon as the other two sides. Apply what you know about triangles and the angle sums in a circle.
2007-01-26 18:23:18 · answer #1 · answered by smartprimate 3 · 0⤊ 0⤋
In your earlier question,i have mentioned that the sum of exterior angles of a polygon is always 360 degrees.In case of a regular polygon,all the angles.shall however be equal.Now,a regular octagon will have 8 equal exterior angles
Therefore,measure of each will be 360/8=45 degrees
2007-01-27 02:41:00 · answer #2 · answered by alpha 7 · 0⤊ 0⤋
from : maryam
In a regular octagon (8 sides and angles), what is the measure of each interior angle and what is the measure of each exterior angle?
The sum of all 8 interior angles is given by .
2007-01-27 05:34:20 · answer #3 · answered by maryam 2 · 0⤊ 0⤋
Remember
A regular octagon is a polygon
The sum of interior angles of a polygon is dependent on the number of sides but the sum of the exterior angles is always 360º .
Theorem: The sum of the exterior angles of a polygon is 360º.
A regular octagon has (8 sides and angles), so
360º/8 = 45º.
45º + 45º + 45º + 45º + 45º + 45º + 45º + 45º = 360º
2007-01-27 02:42:32 · answer #4 · answered by Pam 5 · 1⤊ 0⤋
sum of interior angles:
(8-2)180=6*180
=1080 degrees
Each angle measures: 1080/8=135 degrees
Hence, each exterior angle measures: 180-135=45degrees OR
360/8=45degrees
2007-01-27 08:29:42 · answer #5 · answered by Nadz 1 · 0⤊ 0⤋
360/8 = 45 degrees because the sum of the exterior angles = 360 degrees.
2007-01-27 01:48:29 · answer #6 · answered by sahsjing 7 · 1⤊ 0⤋