What is the energy, in joules, of a photon with the wavelength of 700 nm?

Answer 1

The energy in a photon is hc/L where h is planks constant, c is the speed of light and L is Lamda the wavelength. h is equal to 6.63x10^-34 Joule-seconds and the speed of light is 3x10^8 meters/second

So now you can figure out the answer.

Answer 2

convert seven-hundred nm to meters 700nm/10^9nm=7*10^-7 m now the equation for capability is e=hc/lamda the place lambda is your wavelength. planks consistent is 6.626*10^-34 velocity of sunshine 3.0*10^8 so [(6.626*10^-34 J sec)*(3.0*10^*8sec/m)]/7*10^-7 m =2.eighty 4*10^-19 J

Answer 3

E per photon = h*f
= h*c/x
= 6.6262*10^-34 * 3*10^8 / (700*10^-9)
= 2.8398 * 10^-19 J

h=Planck's constant (6.6262*10^-34 J/s)
c=the speed of light (3*10^8 m/s)
x=wavelength(m)

Answer 4

convert 700 nm to meters

700nm/10^9nm=7*10^-7 m

now the equation for energy is e=hc/lamda
where lambda is your wavelength.

planks constant is 6.626*10^-34
speed of light 3.0*10^8

so [(6.626*10^-34 J sec)*(3.0*10^*8sec/m)]/7*10^-7 m
=2.84*10^-19 J