What is the energy, in joules, of a photon with the wavelength of 700 nm?

Answer 1

The energy (E) of a photon of light with a given wavelength (lambda) can be found as,
E = h * (c / lambda)
where h is Planck's constant (6.63 E-34 J s)
and c is the speed of light in a vacuum (3 E8 m/s).

We are given a value for lambda,
lambda = 700 E-9 meters,
so all we do now is plug into the equation and solve.

E = (6.63 E-34 J s) (3 E8 m/s) / (7 E-7 m)
E = 2.841 E-19 Joules

Answer 2

convert 700 nm to meters

700nm/10^9nm=7*10^-7 m

now the equation for energy is e=hc/lamda
where lambda is your wavelength.

planks constant is 6.626*10^-34
speed of light 3.0*10^8

so [(6.626*10^-34 J sec)*(3.0*10^*8sec/m)]/7*10^-7 m
=2.84*10^-19 J

Answer 3

E = (plancks constant x speed of light) / wavelength
put 700nm in meters
SOLVE

Answer 4

eleventeen

Answer 5

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