I assume it would be the same as the volume of a cone, which is:
(pi/3)*radius^2 * height.
radius is the 1/2 the diameter of the base of the cone
2007-01-26 16:42:14
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answer #1
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answered by Anonymous
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a very interesting question !
It depends on the measure of the pile
But also how long has the pile be like this ?
the denisity of the sand
I will go for this :
assume the surface is a cricle, measure its radius r
assume its cone like pile , meaure the height : h
then the volume = 1/3 Ï r^2 h
you can adjust this with a factor 0 < f <= 1 for the density of the sand , because you dont want to count the space between the sand grains a volume ( i wont pay for it ! )
May I ask you why you want to know this ?
Are you working in the sand industry ?
2007-01-27 03:48:52
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answer #2
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answered by gjmb1960 7
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It depends on the shape of your sand pile. If you were making a sand castle, -- usually, you have a pile in the shape of your sand PAIL which is close to the shape of a right cylinder. Then the volume is approximately V = area of the bottom circle x the height of the cylinder or V = pi x r^2 x h
If it is a cone shaped pile then it is one third (1/3) of the value of the volume above.
If it is a rectangular bed, then the
volume is just length x width x height.
2007-01-27 01:03:48
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answer #3
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answered by Aldo 5
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Usually Sand Pile are conical in shape,
So, Volume, V = 1/3(pi)(r)^2(h)
2007-01-27 02:39:19
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answer #4
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answered by razov 2
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I would approximate the cross section of the sand pile with a parabola. That may not be the actual shape but it certainly is more like the shape of the pile than a cone. That is as far as I have thought. There is probably an analytical geometry method for taking some measurements of the the pile and picking a parabola that is close to the right shape.
2007-01-27 01:01:32
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answer #5
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answered by anonimous 6
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assume it would be the same as the volume of a cone, which is:
(pi/3)*radius^2 * height.
radius is the 1/2 the diameter of the base of the cone
2007-01-27 09:49:05
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answer #6
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answered by Anonymous
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