English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

how many ways can you chose a committee of 3 people from a group of 12?
a]3
b]36
c]12
d]72
e]220

toss a coin three times whats the probablity that it lands heads/tails /heads?
a]3/8
b]3/2
c]1/8
d]1/2
e]3/4

2007-01-26 16:07:36 · 5 answers · asked by koalabear 2 in Science & Mathematics Mathematics

5 answers

e and c

12C3 = 12*11*10 / 6 -- easier to calculate

2007-01-26 16:16:01 · answer #1 · answered by oracle 5 · 0 0

precubrem use the formal or draw it out (12!/(12-3)!)/3!=220
chance of getting heads is 1/2 chance of hetting tailes is 1/2 and heads again is 1/2 so 1/2*1/2*1/2 =1/8

note* = is times

2007-01-27 00:29:20 · answer #2 · answered by derek48316 3 · 0 0

1. 12C3 = 220 -- combinations question..order doesnt matter
12!/(9! * 3!)

2. 0.5 * 0.5 * 0.5 = 1/8 -- independant events

2007-01-27 00:13:11 · answer #3 · answered by Bored 2 · 2 0

C(12;3)=12!/((12-3)! 3!)
=10.11.12/6
=220
e) is true


(1/2)^3
=1/8
c) is true

2007-01-27 00:27:30 · answer #4 · answered by iyiogrenci 6 · 0 0

answer to first : e
answer to second :c

2007-01-27 00:20:22 · answer #5 · answered by sam 1 · 0 0

fedest.com, questions and answers