QUESTION : when twice a number is increased by 20 the result 48 plus the number
2007-01-26 15:34:58 · 5 answers · asked by chiquilla8595 1 in Science & Mathematics ➔ Mathematics
Let x be the number.
"Twice a number is increased by 20" means
2x + 20
"The result" means we use an equal sign for the equation, "="
"48 plus the number" means 48 + x.
Translation?
2x + 20 = 48 + x
Now, use basic algebra to solve this.
x = 28
2007-01-26 15:41:12 · answer #1 · answered by Puggy 7 · 1⤊ 0⤋
Let n be the number in question. Set up your equation according to the wording of the problem.
2n + 20 = n + 48 From here you can continue 1 of 2 ways.
2n - n = 48 - 20 or 2n = n + 28
n = 28
Proof: Twice 28 (56) is increased by 20 (76) the result 48 + 28.
2007-01-27 00:25:13 · answer #2 · answered by Marv 2 · 0⤊ 0⤋
Numerical data: 2x + 20 = 48 + x
*Combine "like" terms...
First: subtract "20" from both sides (When you move a variable to the opposite side, always use the opposite sign)....
2x + 20 - 20 = 48 + x - 20
2x = 48 - 20 + x
2x = 28 + x
Sec: subtract "x" from both sides....
2x - x = 28 + x - x
x = 28
2007-01-26 23:45:49 · answer #3 · answered by ♪♥Annie♥♪ 6 · 1⤊ 0⤋
if x is the unknown
2x+20 = x + 48
2x-x+20=48
x+20=48
x=28
double check...
28*2 = 56, 56+20=76
28+48=76
2007-01-26 23:50:40 · answer #4 · answered by spacey_post 2 · 0⤊ 0⤋
2x+20=x+48 subtract x+20 from each side
x=28
2007-01-26 23:42:02 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋