A person sittting on the top of the tall biulding drops ball at regular interval of one second. Find the position of the 3rd, 4th, 5th ball when the 6th ball is dropped?
2007-01-26 13:41:29 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
i think
3rd to 4th ball will have the greatest distance tihin each other.
4th to 5th would be closer apart. because the balls take time to accelerate.
and when you drop the 6th, 5th to 6th distance would be d smallest.
2007-01-26 13:49:51 · answer #1 · answered by jon 2 · 0⤊ 1⤋
Ok, the 6th ball is dropped 1 second after the 5th ball. So, after ONE second, the 5th ball has fallen
1/2 g t^2 = 16 ft
The 6th ball is dropped 2 seconds after the 4th ball. So, after two seconds, the 4th ball has fallen 1/2*32*4 = 64 ft
The third ball has fallen 1/2*32*9 = 16*9 = 144 ft
2007-01-26 21:49:22 · answer #2 · answered by firefly 6 · 0⤊ 0⤋
1) Let h(n) be the distance the nth ball has fallen
2) h(n) = ( g * ( 6 - n ) ^ 2 ) / 2; where g is the gravitational constant; about 32.2 ft/sec/sec.
3) h(3) = 9 * g / 2; third ball
4) h(4) = 4 * g / 2; fourth ball
5) h(5) = 1 * g / 2; fifth ball
2007-01-26 22:21:04 · answer #3 · answered by 1988_Escort 3 · 0⤊ 0⤋