What's the molecular geometry of the following molecules: XeOF4, SF4, FOF, BrF3, XeF2?

Question

And by molecular geometry I mean, for example, Bent, seesaw, square pyramidal, linear, octagonal, etc.

And, thanks in advance for the help!

Answer 1

These are hard problems!

BrF3 has the bromine and fluorines in a plane, but has 2 extra pairs of electrons which make it hard to catagorize what the exact structure of the moloecule difficult - but it is planar with respect to the atoms,

XeOF4 - I could even find that one! - have no idea - but I'd expect it's a coordination compound ( no ideal what is coordinated where though? - sorry)

SF4- here's a reference for you:
http://lb.chemie.uni-hamburg.de/static/data/24_mrfhzsna.html
It exist as a dimer not as a single molecule, and it isn't tetrahedral - like carbon - but I'd guess you'd call it kind of square (but twisted) - no data to back that up - .....

XeF2 - is linear - WIKI ref http://en.wikipedia.org/wiki/Xenon_difluoride

Sorry, that's the best I could come up with - you stump me with that one!

Answer 2

Xeof4 Molecular Geometry

Answer 3

You have to use the VSEPR model. First determine the total amount of valance electrons available. Then create the skeleton structure and assign the electron pairs aroung the terminal atoms and then the central atom. Use double / triple bonds as necessary to achieve octet. I suspect your Xe compounds will be exceptions to the octet and will hold more than 8 electrons on the central atom.

Then you can look on the VSEPR chart and get the shape and polarity.

Answer 4

XeOF4- tetrahedral
SF4- tetrahedral
FOF- Bent (2 lone pairs on oxygen)
BrF3- Trigonal Planar
XeF2-Bent (2 lone pairs on Xe, does not break any octet rules in this example though)

Answer 5

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