B- Brunnette
b- blonde
E-blue eyes
e- blue eyes
A heterozygoes brunnete male with blue etes has children with a heterozygoes female with brown eyes and blonde hair.
what is teh possibility of
a.) blonde blue eyed boy's
b.) brunnete blue eyed girl's
c.) brown eyed blond boy's
d.) brunette beown eyed girl's
plz plz plz help me ! plz someoen juss tell me this ! i swear ill give u the 10 points for ethe first person who answers coreectly!
2007-01-26 12:53:08 · 8 answers · asked by jessica93sz3 3 in Education & Reference ➔ Homework Help
B b
E EB Eb
e eB eb
a.) 25%
b.) 25%
c.) 25%
d.) 25%
I'm guessing for e you meant Brown eyes but this is as simple as you can get in genetics.
and guy above me, the probability of you passing math class is 0/10, probability is fractions dumbass, chance is percentage.
2007-01-26 13:17:43 · answer #1 · answered by justinstrong01 1 · 1⤊ 0⤋
Punnett squares were never my thing. Are you sure you typed the question correctly? If the female shows the recessive traits, she can't be heterozygous, she must be homozygous for the recessive traits. If she were heterozygous, then she would show the dominant trait, since the dominant trait is present and is "dominant" over the other trait. Dihybrid cross between a heterozygote and a homozygote (recessive):
a) 4/16 = 1/4 = 25%
b) 25%
c) 25%
d) 25%
i'm not 100% sure, but the website below is a great resource...
2007-01-26 13:26:05 · answer #2 · answered by Krimo 2 · 1⤊ 0⤋
use a dihybrid cross:
results: 25% blonde blue eye boy
25% blonde brown eye boy
25% brunette brown eye girl
25% brunette blue eye girl
50% chance by, 50% girl, do a dihybrid cross and find that 4 boxes apply to each. since there are 16 total boxes, 16/4 = 4, so 1/4 of each
Hope this helps! I <3 genetics!
2007-01-26 13:18:41 · answer #3 · answered by Lady_Eagle410 3 · 1⤊ 0⤋
a million) 12(t^2-t-2)=(t+a million)(t-2) very final answer is 12(t+a million)(t-2) 2) M^2+5m+6=(m+3)(m+2) 3) w^2-4w-12=(w+2)(w-6) 4) f^2+3f-10=(f+5)(f-2) 5)h^2+3h-10=(h+5)(h-2) 6)m^2-5m-24=(m+3)(m-8) 7)16x-fifty six+6dx-21d=(3-D+8)(2x-7) 8) 18r^2+12ry-3xr-2xy=(6r-x)(3r+2y) 9)4-2q-6p+3pq=(2-q)(-3p+2))
2016-11-01 09:25:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
The question is probably looking for a Punnett Square.
2007-01-26 13:05:49 · answer #5 · answered by Nikki 2 · 0⤊ 2⤋
the probability of you passing spelling class is 16%
2007-01-26 13:13:47 · answer #6 · answered by Anonymous · 0⤊ 2⤋
You have to do a Punnett Square.
2007-01-26 13:08:38 · answer #7 · answered by Patrice B 2 · 0⤊ 2⤋
d
2007-01-26 13:03:16 · answer #8 · answered by blondiee 1 · 0⤊ 2⤋