Here is how you prove that -40 is the point where they are the same.
Use the formula: Tc = (5/9)*(Tf-32)
Now set Tc = Tf and solve for Tf
Tf = (5/9)(Tf-32)
9/5Tf = Tf - 32
Tf - 9/5Tf = 32
Tf(1-9/5) = 32
Tf = 32 / (1-9/5) = 32 / (-4/5) = 32 * (-5/4) = -160/4 = -40
2007-01-26 12:27:21
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answer #1
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answered by Alan Turing 5
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They are the same at -40 degrees.
2007-01-26 20:20:11
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answer #2
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answered by Kyle 2
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At roughly -40 degrees, they're the same
2007-01-26 20:22:07
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answer #3
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answered by Anonymous
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-40 degrees
2007-01-26 20:20:31
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answer #4
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answered by Barkley Hound 7
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-40deg F= -40deg C
Formula: F=(9/5)C + 32
2007-01-26 20:22:19
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answer #5
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answered by HORGA 2
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-40 degrees
233.15Kelvin
2007-01-26 20:23:37
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answer #6
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answered by matt the librarian 3
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at -40 on both scales
2007-01-26 20:19:20
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answer #7
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answered by Kerahna 3
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It's actually -140 degrees
2007-01-26 21:50:11
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answer #8
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answered by rock_man 3
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i believe its -40, but not totally sure
2007-01-26 20:19:53
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answer #9
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answered by J_shizzle 2
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never
2007-01-26 20:20:45
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answer #10
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answered by Aaron A 5
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