Help me please!!! I need help with calculus problem?

Question

Find the slope of the line containing the following pts (3/8,-5) and (-1/4,-1/4). Also, could you please explain to me how you arrived at the answer?

I really appreciate your help!!! :)

Answer 1

This isn't calculus, it's simple algebra.

slope = (y2 - y1) / (x2 - x1)

(-1/4 + 5) / (-1/4 - 3/8) = (4 3/4) / (-5/8)

-38/5

Answer 2

Well, firstly, this isn't calculus; this is analytical geometry. I suppose some people might call it pre-calculus or something, but it definetly isn't.

As you probably know, the equation of a line is y=mx + b, where m is the slope and b is the y-intercept.

To calculate m, you can use the formula m = [y2 - y1] / [x2 - x1] , where (x1, y1) and (x2, y2) are two points on the line.

So for your question, m (slope) is equal to -38/5

m = [(-5) - (-1/4)] / [(3/8) - (-1/4)]
m = (- 38/8) / ( 5/8)
m = -38/5 = -7 3/5

The slope of your line is -38/5

Answer 3

The slope m, of a line is the change in y divided by the change in x.

m = [-1/4 - (-5)]/[-1/4 - 3/8] = (19/4)/(-5/8) = -38/5

Answer 4

ok we have (3/8 , -5) that is (x1, y1)
and (-1/4, -1/4) that is (x2, y2)

slope= (y2 - y1)/(x2 - x1)

so:
slope= (-1/4 - (- 5))/(-1/4 - 3/8)

slope= (-1/4 + 5)/ (- 5/8)

slope= -38/5

slope= tan -7.6

slope= 82.5º



that's it. I hope you understand me

Answer 5

m=(y2-y1)/(x2-x1)

so, you say m = (-5--1/4)/(3/8--1/4) = (-21/4)/(5/8) = -168/20 = 84/10 = 42/5.
This is actually algebra 1.