easy Q :just make sure..is that right or not !!?

Question

the Q is : 12x^2 -3 =?
i solve it like this : 3(4x^2-1)
so i don't know is that it..or i must complete it and do it like this : 3(4x-1)(4x-1)
thanx

Answer 1

it actually be (2x-1) (2x+1).
x would be 1/2 and -1/2

Answer 2

You should take it beyond 3(4x^2 - 1).

But your final step is wrong. 4x^2 - 1 is not (4x - 1)(4x - 1) as you will see if you multiply it out. You can also see it by letting x = 5 and seeing is it true:

Is 4(5²) - 1 = (20 - 1)(20 - 1) ? No.

Does the phrase "the difference of two squares" mean anything to you? This is a handy formula which is well worth remembering:

a² - b² = (a - b).(a + b)

Answer 3

almost..you got it right until the end: you factored the (4x^2-1) wrong
heres how to do it:
you have to use the difference of squares method, a^2-b^2=(a+b)(a-b)
so yours turns out to be (2x+1)(2x-1)
then multiply by 3: 3(2x+1)(2x-1)
and thats the answer

Answer 4

Your first step is correct. The second step is incorrect.

3(4x^2-1)
the way you have it the answer is 3(16x^2-8x+1)

The answer is 3(2x-1)(2x+1)
negative x positive=negative

Answer 5

answer is : 3(2x+1)(2x-1)

4x^2-1 = (2x+1)(2x-1)

Answer 6

It should be: 3(2x+1)(2x-1)
-----------
Reason:
4x^2-1
=(2x)^2-1
=(2x+1)(2x-1)

Answer 7

i don't think that's right. cuz that (4x-1)(4x-1) doesn't work out. try multiplying it out. it = 4x^2-8x+1...and that's not wat u want. i'm pretty sure it's just 3(4x^2-1)