To get the intercepts, first put in 0 for x and solve for y... then put in 0 for y and solve for x...
Y-intercept:
4(0) - 2y = 4
- 2y = 4
y = -2
or point (0, -2)
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X-intercept:
4x - 2(0) = 4
4x = 4
x = 1
or point (1, 0)
Now put those on the coordinate plane and connect the dots.
2007-01-26 11:12:44
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answer #1
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answered by Mathematica 7
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To get the intercepts, first put in 0 for x and solve for y... then put in 0 for y and solve for x...
Y-intercept:
4(0) - 2y = 4
- 2y = 4
y = -2
or point (0, -2)
-------
X-intercept:
4x - 2(0) = 4
4x = 4
x = 1
2007-01-26 11:15:21
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answer #2
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answered by Anonymous
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What are the x- and y-intercepts of the graph of 4x 3y = 36? I THINK THERE IS AN ADDITION SIGN MISSING IN FRONT OF 3Y 4x + 3y = 36 **********x-int (either set y to 0 OR just cover up the 3y term and solve for x) x =9 **********y-int (either set x to 0 OR just cover up the 4x term and solve for y) y =12 a.) x-intercept: 12, y-intercept: 9 b.) x-intercept: 9, y-intercept: 12**********ANSWER c.) x-intercept: 9, y-intercept: 12**********Same answer as b.) d.) x-intercept: 12, y-intercept: 9 Which is the slope of the line with equation 4x 2y = 4? AGAIN A "+" SIGN MISSING 4x+2y=4 To find the slope either solve for y and write coefficient of x as the slope OR FASTER Divide the coefficient of X by the coefficient of Y and change the sign of (ONLY) one of the answer 4/2=2 slope is -2 a.) -2*************ANSWER b.) -1/2 c.) 1/2 d.) 2 Which pair of equations represents two perpendicular lines? FIND THE SLOPE OF EACH LINE PERPENDICULARS ARE NEGATIVE RECIPROCALS or YOU CAN SEE WHICR MULTIPLY TO -1 a.) -3x + 2y = 10 and 3y = -2x + 12 -3/2.....m=+3/2 :::::::::::y=-2/3x+4........m=-2/3 These are Neg. Rec or (+3/2)(-2/3) = -1 a.) IS THE *****************ANSWER b.) 2x + 5y = 45 and y + 2/5x = -9 THESE happen to be parallel as they have the same slope (m=-2/5) c.) x = 4y + 4 and 4x = 4y = 4 .....x = 4y + 4 and 4x + 4y = 4 ...................................*..... to a PLUS Lines intersect NO relation between the slopes......m1=4.....m2=-1 d.) 7x + 4y = 20 and y - 3 = - 4/7x These slopes are reciprocals but not negative of each other m=-7/4...................................
2016-04-10 21:45:34
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answer #3
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answered by Anonymous
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4x-2y=4
can be rewritten as
4x/4-2y/4=1
or
x/1-y/2=1
Thus x-intercept is (1,0) and y-intercept is (0,-2).
Mark off points (1,0) on x-axis and (0,-2) on y-axis, and draw a line passing through the two points.
This is the line whose equation is 4x-2y=4.
2007-01-26 11:19:32
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answer #4
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answered by asumsrkumar 1
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4x 2y 4
2016-12-17 11:52:44
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answer #5
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answered by mordehay 4
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4x - 2y = 4
2x - y = 2
-y = -2x + 2
y = 2x - 2
0 = 2x - 2
2 = 2x
x = 1
y = 2(0) - 2
y = 0 - 2
y = -2
the intercepts are (1,0) and (0,-2)
2007-01-26 15:29:11
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answer #6
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answered by Sherman81 6
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this is a linear graph...
letting x=0
y = -2
letting y =0
x= 1
therefore plottin those points (0,-2) and (0,1) on a cartesian axis u would get a positive gradient graph
2007-01-26 11:13:33
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answer #7
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answered by Forever happy 3
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