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-3 . .. .. .. . . 2x
___ . .. - .... ___
x+1 . .. ... .. -x -1
________________
-10
_____ + 4
x+1

2007-01-26 10:41:46 · 9 answers · asked by Doug 2 in Science & Mathematics Mathematics

9 answers

First one stays the same: -3/(x+1)

2x/(-x-1) = -2x/(x+1)

So on top you now have:

-3/(x+1) + 2x/(x+1) = (2x-3)/(x+1)
----------
Bottom:
-10/(x+1) is fine

You need to get a common denominator for the 4...
4(x+1)/(x+1) = (4x + 4)/(x+1)

So now you have:
-10/(x+1) + (4x+4)/(x+1) =
(4x - 6)/(x+1) =
[2(2x - 3)]/(x+1)
----------
when you have (a/b)/(c/d) = ad/bc

So...

[(2x-3)(x+1)]/[(x+1)(2)(2x - 3)]

The (x+1) and (2x -3) on top and bottom cancel.
You're left with 1/2

2007-01-26 10:49:08 · answer #1 · answered by Mathematica 7 · 0 0

(5z ? 5)/21 ÷ (z ? a million)/(14z) = First, attempt to confirm if something factors out. interior the staggering of the 1st fraction (z ? a million) factors out. In the two fractions 7 factors out. (5z ? 5)/21 ÷ (z ? a million)/(14z) = 5(z ? a million)/(3·7) ÷ (z ? a million)/(2·7z) = Divide the staggering and cancel out the backside. 5(z ? a million)/(3·7) ÷ (z ? a million)/(2·7z) = 5/3 ÷ a million/(2z) = Now that is somewhat much less perplexing. we alter ÷ into · (branch into multiplication) and turn the 2d fraction over getting its reciprocal. 5/3 ÷ a million/(2z) = 5/3 · 2z = Multiply. 5/3 · 2z = 10/3 z = Divide the staggering (10) by utilising the backside (3). 10/3 z = 3.(3) z

2016-11-01 09:12:47 · answer #2 · answered by gennusa 4 · 0 0

Numerator = - 3/(x+1) +2x/(x+1) =(2x - 3)/(x+1).

Denominator = (4x-6)/(x+1) =2(2x -3) /(x+1)

So the desired fraction = (1/2) Answer.

2007-01-26 11:02:32 · answer #3 · answered by Anonymous · 0 0

start with the top --> make a constant denominator and subtract them

do the same with the bottom

you'll be left with two fractions -- using the same technqiue as the last question you asked, invert one of the fractions and multiply them together (producing a division instead of a multiplication)

2007-01-26 10:46:16 · answer #4 · answered by mdigitale 7 · 0 0

-3 (-x-1) - 2x
--------------------
(x+1)(-x-1)
________________
-10 + 4(x+1)
--------------------
x+1 by having the same denominator


=3x+1 - 2x x+1
--------------- * -----------
(x+1)(-x-1) -6+4x

= x+1
------------
(-x-1) (-6+4x) (by cancelling the (x+1) from the numerator and denominator

= x+1
--------
-1(x+1) (-6+4x) cancel the x+1 from numerator and denominator

= 1 / (4x-6)

2007-01-26 10:55:14 · answer #5 · answered by K J 1 · 0 0

Here's a better one.

You + Posting math problems on yahoo questions = lame.

2007-01-26 10:47:30 · answer #6 · answered by Soundguy 2 · 0 2

one is the loneliest number

enough with the math porn already, I'll report you

2007-01-26 10:46:55 · answer #7 · answered by kurticus1024 7 · 1 1

ummmmm i honestly dnt give a crap

2007-01-26 10:47:15 · answer #8 · answered by Anonymous · 0 2

hm, ask your teacher. ^_^

2007-01-26 10:47:32 · answer #9 · answered by Anonymous · 0 2

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