Basically, there is X amount of radioactive carbon in every organism. When the organism dies, the carbon starts to decay. It decreases by 50% every 5568±30 years.
For example, if it started out with 1,000 carbon molecules, in 5,568 years, there would be only 500, then 250, then 125, etc...
2007-01-26 10:52:07
·
answer #1
·
answered by Steven M 1
·
1⤊
0⤋
Simple:
Every living tissue (plant or animal) absorbs a certain amount of radioactive carbon isotope (C-14) during its lifetime. Once the plant/animal dies, the carbon starts deteriorating. Every so many thousand years, half of the carbon atoms will have decayed and become a different type of atom.
By analyzing how many total C-14 atoms there are, and how many of the other carbon isotope there are, by a mathematic calculation we can determine the age of the material.
C-14 is fairy accurate. Suffice it to say that it was accurate enough to say that the Shroud of Turin was created/woven/painted a few hundred years after the death of Jesus on the cross. Thus it could not be the shroud used to clothe his body while in the grave.
Clear enough?
2007-01-26 10:52:22
·
answer #2
·
answered by anon 5
·
0⤊
0⤋
A very small % of C on Earth is called C-14. It is one isotope of normal C (known as C-12). C-14 happens to be a radio-isotope which will decompose through nuclear decay to form N. While things are alive they constantly bring in new C (and C-14) through ingestion of C-based food and CO2. When an organism dies it no longer brings in more C. The C-12 does not change, but the C-14 will decompose at a known rate over time. You measure the amount of C-14 left in the sample and can calculate how long that material has been lifeless. C-14 dating only works on things that were once alive. It does not work on rocks because they don't contain C.
2007-01-26 10:47:33
·
answer #3
·
answered by physandchemteach 7
·
1⤊
0⤋
Just works on living things that have died.
Cosmic rays enter the earth's atmosphere in large numbers every day. For example, every person is hit by about half a million cosmic rays every hour. It is not uncommon for a cosmic ray to collide with an atom in the atmosphere, creating a secondary cosmic ray in the form of an energetic neutron, and for these energetic neutrons to collide with nitrogen atoms. When the neutron collides, a nitrogen-14 (seven protons, seven neutrons) atom turns into a carbon-14 atom (six protons, eight neutrons) and a hydrogen atom (one proton, zero neutrons). Carbon-14 is radioactive, with a half-life of about 5,700 years.
As soon as a living organism dies, it stops taking in new carbon. The ratio of carbon-12 to carbon-14 at the moment of death is the same as every other living thing, but the carbon-14 decays and is not replaced. The carbon-14 decays with its half-life of 5,700 years, while the amount of carbon-12 remains constant in the sample. By looking at the ratio of carbon-12 to carbon-14 in the sample and comparing it to the ratio in a living organism, it is possible to determine the age of a formerly living thing fairly precisely
How radioactive the carbon-14 is determines how old it is.
2007-01-26 10:50:21
·
answer #4
·
answered by Steven A 3
·
1⤊
0⤋
ok, C-14 is radioactive, which means it radiates particles. it will be converted into C-13 by the rate of its half life.
in other words it takes so long fo half of it to become nucleially stable
C-14 has a half lif of 5730 years, which means with a certain equation, it is possible to calculate how old something is by how much C-14 is left in the object
2007-01-26 10:51:23
·
answer #5
·
answered by Gino R 2
·
0⤊
0⤋
I used to believe in it
they just show some sexy samples from the cretacious or the devonian
then it doesn't seem to pan out unless you pay the $6.95
even then the best samples are taken and/or crazy
2007-01-26 10:48:59
·
answer #6
·
answered by kurticus1024 7
·
0⤊
0⤋
This should help
http://www.howstuffworks.com/carbon-14.htm
2007-01-26 10:49:27
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
.I would tell you if i remembered but go to http://www.christiananswers.net/q-aig/aig-c007.html. that will probably help you.
2007-01-26 10:50:28
·
answer #8
·
answered by Gavi 3
·
0⤊
0⤋